(x^5-6x³+7x²-7x+3)÷(x³-2x+1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 16:58:22
x)Ө35PS6463,u+5o׀JUhj$铦AΆ; ㌁jl M4CjDM+uu6<ٽi˻m
:
4k`l@N K
(x^5-6x³+7x²-7x+3)÷(x³-2x+1)
(x^5-6x³+7x²-7x+3)÷(x³-2x+1)
(x^5-6x³+7x²-7x+3)÷(x³-2x+1)
x^5-6x^3+7x^2-7x+3=(x^2-4)(x^3-2x+1)+6x^2-15x+7,所以原始=x^2-4+(6x^2-15x+7)|x^3-2x+1