lim(x→∞)=(7x³-x²+3)/(6x²+5x+2)=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/03 04:34:36
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lim(x→∞)=(7x³-x²+3)/(6x²+5x+2)=?
lim(x→∞)=(7x³-x²+3)/(6x²+5x+2)=?
lim(x→∞)=(7x³-x²+3)/(6x²+5x+2)=?
楼主问题的书写有问题呀.
是要求lim(x→∞)(7x³-x²+3)/(6x²+5x+2)吧?
如果是的话:
这个没有给完整的式子,应该是lim(x→∞)(3x³-4x²+2)/(7x³+5x²-3)=lim(x→∞)[3-(4/x)+(2/x³)]/[7+(5/x)-(3/x³)]=3/7(希望能帮到你,麻烦在我回答的下面点击 “好评”,谢谢你啦^_^)
无穷大
简单判断 分子比分母高了一个次幂~