二元一次方程组:10、甲、乙二人解方程组{ax+y=2,2x-by=1.}甲看错a得解{x=1,y=1.}乙看错b得解{x=1,y=2}则a=________,b=________,原方程组的解为__________.
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![二元一次方程组:10、甲、乙二人解方程组{ax+y=2,2x-by=1.}甲看错a得解{x=1,y=1.}乙看错b得解{x=1,y=2}则a=________,b=________,原方程组的解为__________.](/uploads/image/z/1999759-31-9.jpg?t=%E4%BA%8C%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%E7%BB%84%EF%BC%9A10%E3%80%81%E7%94%B2%E3%80%81%E4%B9%99%E4%BA%8C%E4%BA%BA%E8%A7%A3%E6%96%B9%E7%A8%8B%E7%BB%84%EF%BD%9Bax%2By%3D2%2C2x-by%3D1.%7D%E7%94%B2%E7%9C%8B%E9%94%99a%E5%BE%97%E8%A7%A3%EF%BD%9Bx%3D1%2Cy%3D1.%7D%E4%B9%99%E7%9C%8B%E9%94%99b%E5%BE%97%E8%A7%A3%7Bx%3D1%2Cy%3D2%7D%E5%88%99a%3D________%2Cb%3D________%2C%E5%8E%9F%E6%96%B9%E7%A8%8B%E7%BB%84%E7%9A%84%E8%A7%A3%E4%B8%BA__________.)
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