在三角形ABC中,角ABC所对的边 分别是a b c已知向量M=(cos2分之3B,sin2分之3B)向量N=(cos2分之B,sin2分之B)并且满足向量M+向量N的模=根号3 1、求角B的大小 2、若b=3sinC=2sinA 求
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 07:05:03
![在三角形ABC中,角ABC所对的边 分别是a b c已知向量M=(cos2分之3B,sin2分之3B)向量N=(cos2分之B,sin2分之B)并且满足向量M+向量N的模=根号3 1、求角B的大小 2、若b=3sinC=2sinA 求](/uploads/image/z/2002516-52-6.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92ABC%E6%89%80%E5%AF%B9%E7%9A%84%E8%BE%B9+%E5%88%86%E5%88%AB%E6%98%AFa+b+c%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8FM%3D%EF%BC%88cos2%E5%88%86%E4%B9%8B3B%2Csin2%E5%88%86%E4%B9%8B3B%EF%BC%89%E5%90%91%E9%87%8FN%3D%EF%BC%88cos2%E5%88%86%E4%B9%8BB%2Csin2%E5%88%86%E4%B9%8BB%EF%BC%89%E5%B9%B6%E4%B8%94%E6%BB%A1%E8%B6%B3%E5%90%91%E9%87%8FM%EF%BC%8B%E5%90%91%E9%87%8FN%E7%9A%84%E6%A8%A1%EF%BC%9D%E6%A0%B9%E5%8F%B73%E3%80%80%E3%80%80%E3%80%80%E3%80%80%E3%80%801%E3%80%81%E6%B1%82%E8%A7%92B%E7%9A%84%E5%A4%A7%E5%B0%8F%E3%80%80%E3%80%802%E3%80%81%E8%8B%A5b%EF%BC%9D3sinC%EF%BC%9D2sinA%E3%80%80%E6%B1%82)
xR]kA+зݙIm}տ ӬdFmL*TjEktw>/8iF4υ3w99\PH6{|ݙw3&1VM˽oLr7Yyn4yFddrxk7yڅ|"!2]s3_;!q)݊viԷߩFCL_C|T