先化简,再求值① [(a+2b)²+(a-2b)(a+2b)]÷2a其中a=2008,b=-2007
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先化简,再求值① [(a+2b)²+(a-2b)(a+2b)]÷2a其中a=2008,b=-2007
先化简,再求值
① [(a+2b)²+(a-2b)(a+2b)]÷2a
其中a=2008,b=-2007
先化简,再求值① [(a+2b)²+(a-2b)(a+2b)]÷2a其中a=2008,b=-2007
[﹙a+2b﹚²+﹙a-2b﹚﹙a+2b﹚]÷2a
=﹙a+2b﹚﹙a+2b+a-2b﹚÷2a
=﹙a+2b﹚·2a÷2a
=a+2b
当a=2008,b=﹣2007时.
原式=2008-2×2007
=﹣2006.