lim/x→1 x^3-3x^2+2/x^3-x^2-x+1利用罗比塔法则求极限

lim(x→1)(x^3-3x+2)/(x^3-x^2-x+1) lim(x→1)[(x^(3x-2)-x)sin2(x-1)]/(x-1)^3 lim x→∞(2x+1)/(3x-4) lim(x→0)2x^3-x+1 lim((√1+x^2)+x)/((√x^3+x)-x)x→+无穷大 lim(x->无穷大){(2^x-3^x)/2}^(1/x) lim(x->0)((2-x)/(3-x))^1/x 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim(x+1)^x+1(x+3)^x+3/x^2x+4 x趋于无穷 lim(x→∞)(4x^3+2x-1)/(2x^3-3x+1) lim(x→∞)(2x^3-x^2-3)/(x^3-x+1) lim x→1 (x^2-4x+3)/(x^4-4x^2+3) lim(x→∞)[（x^3+x^2+x^1+1)^(1/3) - x] 的极限. lim x→0 (x^2+2x-1)/(x^3-2x)的极限是多少 lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) = lim(x→0)[(1+X)(1+2X)(1+3x)-1]/x lim √（3-x）-√（1+x）/x平方+x-2x→1 lim(x→∞)(x^2+x)/(x^4-3x-1)的极限