max=Y3-Y1-Y2;Y1=(A(1,1)*M0(1,1)+A(1,2)*M0(1,2)+A(1,3)*M0(1,3)+A(1,4)*M0(1,4)+A(1,5)*M0(1,5)+A(2,1)*(1+x*0.01)*M0(2,1)+A(2,2)*(1+x*0.01)*M0(2,2)+A(2,3)*(1+2*x*0.01)*M0(2,3)+A(2,4)*(1+2*x*0.01)*M0(2,4)+A(2,5)*(1+2*x*0.01)*M0(2,5)+A(3,1)*(1+2*x*0.01)*M0

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max=Y3-Y1-Y2;Y1=(A(1,1)*M0(1,1)+A(1,2)*M0(1,2)+A(1,3)*M0(1,3)+A(1,4)*M0(1,4)+A(1,5)*M0(1,5)+A(2,1)*(1+x*0.01)*M0(2,1)+A(2,2)*(1+x*0.01)*M0(2,2)+A(2,3)*(1+2*x*0.01)*M0(2,3)+A(2,4)*(1+2*x*0.01)*M0(2,4)+A(2,5)*(1+2*x*0.01)*M0(2,5)+A(3,1)*(1+2*x*0.01)*M0
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max=Y3-Y1-Y2;Y1=(A(1,1)*M0(1,1)+A(1,2)*M0(1,2)+A(1,3)*M0(1,3)+A(1,4)*M0(1,4)+A(1,5)*M0(1,5)+A(2,1)*(1+x*0.01)*M0(2,1)+A(2,2)*(1+x*0.01)*M0(2,2)+A(2,3)*(1+2*x*0.01)*M0(2,3)+A(2,4)*(1+2*x*0.01)*M0(2,4)+A(2,5)*(1+2*x*0.01)*M0(2,5)+A(3,1)*(1+2*x*0.01)*M0
max=Y3-Y1-Y2;
Y1=(A(1,1)*M0(1,1)+A(1,2)*M0(1,2)+A(1,3)*M0(1,3)+A(1,4)*M0(1,4)+A(1,5)*M0(1,5)+
A(2,1)*(1+x*0.01)*M0(2,1)+A(2,2)*(1+x*0.01)*M0(2,2)+A(2,3)*(1+2*x*0.01)*M0(2,3)+A(2,4)*(1+2*x*0.01)*M0(2,4)+A(2,5)*(1+2*x*0.01)*M0(2,5)+
A(3,1)*(1+2*x*0.01)*M0(3,1)+A(3,2)*(1+2*x*0.01)*M0(3,2)+A(3,3)*(1+4*x*0.01)*M0(3,3)+A(3,4)*(1+4*x*0.01)*M0(3,4)+A(3,5)*(1+4*x*0.01)*M0(3,5)+
A(4,1)*(1+3*x*0.01)*M0(4,1)+A(4,2)*(1+3*x*0.01)*M0(4,2)+A(4,3)*(1+6*x*0.01)*M0(4,3)+A(4,4)*(1+6*x*0.01)*M0(4,4)+A(4,5)*(1+6*x*0.01)*M0(4,5)+
A(5,1)*(1+4*x*0.01)*M0(6,1)+A(5,2)*(1+4*x*0.01)*M0(5,2)+A(5,3)*(1+8*x*0.01)*M0(5,3)+A(5,4)*(1+8*x*0.01)*M0(5,4)+A(5,5)*(1+8*x*0.01)*M0(5,5)+
A(6,1)*(1+5*x*0.01)*M0(6,1)+A(6,2)*(1+5*x*0.01)*M0(6,2)+A(6,3)*(1+10*x*0.01)*M0(6,3)+A(6,4)*(1+10*x*0.01)*M0(6,4)+A(6,5)*(1+10*x*0.01)*M0(6,5))*75;
Y2=@sum(mm(m):(A(1,m)-B(1,m)+500)+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m))+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m)+A(3,m)-B(3,m))+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m)+A(3,m)-B(3,m)+A(4,m)-B(4,m))+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m)+A(3,m)-B(3,m)+A(4,m)-B(4,m)+ A(5,m)-B(5,m))+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m)+A(3,m)-B(3,m)+A(4,m)-B(4,m)+ A(5,m)-B(5,m)+A(6,m)-B(6,m)));
Y3=@sum(nn(n):(B(n,1)+B(n,2)+B(n,3)+B(n,4)+B(n,5))*2250);
@for(mm(m):A(1,m)-B(1,m)+500

max=Y3-Y1-Y2;Y1=(A(1,1)*M0(1,1)+A(1,2)*M0(1,2)+A(1,3)*M0(1,3)+A(1,4)*M0(1,4)+A(1,5)*M0(1,5)+A(2,1)*(1+x*0.01)*M0(2,1)+A(2,2)*(1+x*0.01)*M0(2,2)+A(2,3)*(1+2*x*0.01)*M0(2,3)+A(2,4)*(1+2*x*0.01)*M0(2,4)+A(2,5)*(1+2*x*0.01)*M0(2,5)+A(3,1)*(1+2*x*0.01)*M0
解释什么? 这个都需要你自己去看 只要知道基本的语法熟悉线性规划就能看懂 否则说了也没用 自己找个教程看看吧

max=y1+y2+y37 y1+2 y2+9 y3 y1中的1是写在y的右下方 T表示转置max=y1+y2+y37*y1+2*y2+9*y3 设y1=2^-0.9 y2=2^1.6 y3=(1/2)0.5 则 A,y3>y1>y2 B.y2>y1>y3 C.y1>y3>y2 D.y2>y1>y3 已知点(-2,y1),(-1,y2),(1,y3)都在直线y=-3x+b上,则y1 y2 y3 的大小关系为A.y1>y2>y3 B.y1<y2<y3C.y3>y1>y2 D.y3<y1<y2 已知点(-2,y1),B(-1.y2)和C(3,y3)都在反比例函数y=k²+1/x的图像上,下列结论中正确的是A=y1>y2>y3 B=y1>y3>y2 c=y3>y1>y2 d=y2>y3>y1 设y1=4的0.9次方,y2=8的0.48次方,y3=(1/2)的-1.5次方,则( )A.y3>y1>y2 B.y2>y1>y3 C.y1>y3>y2 D.y1>y2>y3 已知点(-1,y1),(2,y2),(3,y3)在反比例函数y=-k2-1/x的图像上,下列结论中正确的是A.y1>y2>y3 B.y1>y3>y2 C.y3>y1>y2 D.y2>y3>y1 已知正比例函数y=-(k²+1)x(其中k为常数),点(-2,y1),(-3,y2),(1,y3)在它的图象上,则( ) (A)y2<y1<y3(B)y2>y1>y3(C)y2>y3>y1(D)y3<y2<y1 已知点(-1,y1),(2,y2),(3,y3)在反比例函数y=k^2+1/x的图像上,下列结论中正确的是A.y1>y2>y3 B.y1>y3>y2 C.y3>y1>y2 D.y2>y3>y1 若a>1,点(-a-1,y1),(a,y2)、(a+1,y3)都在函数y=x^2的图像上,判断y1、y2、y3的大小 抛物线y=a(x-1)的平方开口向上,A(根号2,y1) B(2,y2)C(-根号3,y3),判断y1,y2,y3的大小 设Y1,Y2,Y3为矩阵A..的三个特征值,则 Y1,Y2,Y3等于?A= 1 -2 40 2 7 0 0 3 已知a>,点(a+1,y1)、(a,y2)、(a+2,y3)都在函数y=x²的图像上,则( )A.y1<y2<y3B.y3<y2<y1 .Cy2 <y1<y3 D.y3<y1<y2 已知反比例函数y=-3/x的图像上有三点A(-3,y1),B(-1,y2),C(2,y3)试比较y1,y2,y3的大小 在反比例函数y=-a²-2/x的图像上有三点(-3,y1)(-1,y2)(2,y3),则函数值y1,y2,y3的大小关系是 若点A(-3,y1),B(-1,y2),C(2,y3)都在抛物线y=2/5x平方上,求y1,y2,y3的大小 现有A(-4,y1),B(-3,y2),C(1,y3)为二次函数y=x^2+4x-5的图像上三点,则y1,y2,y3的大小关系是( )现有A(-4,y1),B(-3,y2),C(1,y3)为二次函数y=x^2+4x-5的图像上三点,则y1,y2,y3的大小关系是( )A.y1 1.若点A(-3,y1),B(-2,y2)C(1.5,y3)是二次函数y=mx^2+2mx+n(m<0)的图像上的三点,则y1,y2,y3之间的大小关系是()A.y1<y2<y3 B.y2<y1<y3 C.y3<y1<y2 D.y1<y3<y22.点(x,x^2+3x+1)不可能在第()象限A. 在反比例函数y=-1/x的图像上有三点(x1,y1)(x2,y2)(x3,y3),若x1>x2>0>x3,则下列各式中正确的是A.y1>y2>y3B.y3>y2>y1 C.y3>y1>y2D.y2>y1>y3