如果函数f(x)满足方程af(x)+f(1除以x)=ax,x∈R且x≠0,a是常数,且a≠正负1.试求f(x)的解析式af(x)+f(1/x)=ax…………①把①中的x换成1/x得:af(1/x)+f(x)=a/x…………②联立①②解得:f(x)=[2a²/(a²-1
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![如果函数f(x)满足方程af(x)+f(1除以x)=ax,x∈R且x≠0,a是常数,且a≠正负1.试求f(x)的解析式af(x)+f(1/x)=ax…………①把①中的x换成1/x得:af(1/x)+f(x)=a/x…………②联立①②解得:f(x)=[2a²/(a²-1](/uploads/image/z/2085154-34-4.jpg?t=%E5%A6%82%E6%9E%9C%E5%87%BD%E6%95%B0f%28x%29%E6%BB%A1%E8%B6%B3%E6%96%B9%E7%A8%8Baf%28x%EF%BC%89%2Bf%281%E9%99%A4%E4%BB%A5x%29%3Dax%2Cx%E2%88%88R%E4%B8%94x%E2%89%A00%2Ca%E6%98%AF%E5%B8%B8%E6%95%B0%2C%E4%B8%94a%E2%89%A0%E6%AD%A3%E8%B4%9F1.%E8%AF%95%E6%B1%82f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8Faf%28x%EF%BC%89%2Bf%281%2Fx%29%3Dax%E2%80%A6%E2%80%A6%E2%80%A6%E2%80%A6%E2%91%A0%E6%8A%8A%E2%91%A0%E4%B8%AD%E7%9A%84x%E6%8D%A2%E6%88%901%2Fx%E5%BE%97%EF%BC%9Aaf%281%2Fx%29%2Bf%28x%29%3Da%2Fx%E2%80%A6%E2%80%A6%E2%80%A6%E2%80%A6%E2%91%A1%E8%81%94%E7%AB%8B%E2%91%A0%E2%91%A1%E8%A7%A3%E5%BE%97%EF%BC%9Af%28x%29%3D%5B2a%26%23178%3B%2F%28a%26%23178%3B-1)
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