作业帮（根号x +1）/(x+3) x属于[0,1/4]急
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/26 20:37:11
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（根号x +1）/(x+3) x属于[0,1/4]急
（根号x +1）/(x+3) x属于[0,1/4]
急
（根号x +1）/(x+3) x属于[0,1/4]急
设根号X+1=T,则X=(T-1)^2=T^2-2T+1
X+3=T^2-2T+4,则(根号X+1)/(X+3)=T/(T^2-2T+4)=1/(T+4/T-2)
因为X属于[0,1/4],则T属于[1,3/2]
T+4/T属于[25/6,5],则所求值域为[1/3,6/13]