函数 (8 16:23:16)已知f(x)是定义域为[0,1],则函数y=f(x2)+f(x+4/3)的定义域为
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/28 05:06:14
![函数 (8 16:23:16)已知f(x)是定义域为[0,1],则函数y=f(x2)+f(x+4/3)的定义域为](/uploads/image/z/2088101-29-1.jpg?t=%E5%87%BD%E6%95%B0+%288+16%3A23%3A16%29%E5%B7%B2%E7%9F%A5f%28x%29%E6%98%AF%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%5B0%2C1%5D%2C%E5%88%99%E5%87%BD%E6%95%B0y%3Df%28x2%29%2Bf%28x%2B4%2F3%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B)
x){ھ
fVFVfOoz>iF럮dgmcc&DS-P667|>Y@6IE<>/h`_\g+ "G
函数 (8 16:23:16)已知f(x)是定义域为[0,1],则函数y=f(x2)+f(x+4/3)的定义域为
函数 (8 16:23:16)
已知f(x)是定义域为[0,1],则函数y=f(x2)+f(x+4/3)的定义域为
函数 (8 16:23:16)已知f(x)是定义域为[0,1],则函数y=f(x2)+f(x+4/3)的定义域为
0