已知:如图三角形ABC中,角ACB=90度,CD垂直于AB于d,AE平分角BAC且AC=EF求证:EF平行于BC.
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![已知:如图三角形ABC中,角ACB=90度,CD垂直于AB于d,AE平分角BAC且AC=EF求证:EF平行于BC.](/uploads/image/z/2089912-40-2.jpg?t=%E5%B7%B2%E7%9F%A5%3A%E5%A6%82%E5%9B%BE%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92ACB%EF%BC%9D90%E5%BA%A6%2CCD%E5%9E%82%E7%9B%B4%E4%BA%8EAB%E4%BA%8Ed%2CAE%E5%B9%B3%E5%88%86%E8%A7%92BAC%E4%B8%94AC%3DEF%E6%B1%82%E8%AF%81%3AEF%E5%B9%B3%E8%A1%8C%E4%BA%8EBC.)
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