4(3x+1)²-9=0 x=?
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4(3x+1)²-9=0 x=?
4(3x+1)²-9=0 x=?
4(3x+1)²-9=0 x=?
4(3x+1)²-9=0
(3x+1)²=9/4
3x+1=±3/2
3x=-5/2或3x=1/2
x1=-5/6 x2=1/6
4(3x+1)²-9=0
[2(3x+1)+3][2(3x+1)-3]=0
(6x+5)(6x-1)=0
x1=-5/6, x2=1/6
去括号吧!然后化为一元二次方程式就可以解了啊
4(3x+1)²=9
(3x+1)²=9/4
3x+1=±3/2
3x=-1±3/2
故x=-(1/3)±(1/2)=1/6或-5/6