作业帮2x²y-[x²y+2（x²y-xy)]+y 其中x²=2x+1 y=2011/2012
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![2x²y-[x²y+2（x²y-xy)]+y 其中x²=2x+1 y=2011/2012](/uploads/image/z/2108101-13-1.jpg?t=2x%26%23178%3By-%5Bx%26%23178%3By%2B2%EF%BC%88x%26%23178%3By-xy%29%5D%2By+%E5%85%B6%E4%B8%ADx%26%23178%3B%3D2x%2B1+y%3D2011%2F2012)
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2x²y-[x²y+2（x²y-xy)]+y 其中x²=2x+1 y=2011/2012
2x²y-[x²y+2（x²y-xy)]+y 其中x²=2x+1 y=2011/2012
2x²y-[x²y+2（x²y-xy)]+y 其中x²=2x+1 y=2011/2012
2x²y-[x²y+2（x²y-xy)]+y
=2x²y-x²y-2x²y+2xy+y
=-x²y+2xy+y
=-y[x²-(2x+1）]
∵x²=2x+1
∴2x²y-[x²y+2（x²y-xy)]+y=0