x²+4x+8=2x+11
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![x²+4x+8=2x+11](/uploads/image/z/2110007-47-7.jpg?t=x%26%23178%3B%2B4x%2B8%3D2x%2B11)
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x²+4x+8=2x+11
x²+4x+8=2x+11
x²+4x+8=2x+11
x²+4x+8-2x-11=0
x²+2x-3=0
a=1,b=2,c=-3,那么b²-4ac=4+12=16
所以x1=[-b+√(b²-4ac)]/2a=(-2+4)/2=1,
x2=[-b-√(b²-4ac)]/2a=(-2-4)/2=-3
打字不易,