函数fx=2asin²x-2√3asinxcosx+a+b,x属于(0,π/2)值域[-5,1],求a,b
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 23:56:00
![函数fx=2asin²x-2√3asinxcosx+a+b,x属于(0,π/2)值域[-5,1],求a,b](/uploads/image/z/2110021-61-1.jpg?t=%E5%87%BD%E6%95%B0fx%3D2asin%26%23178%3Bx-2%E2%88%9A3asinxcosx%2Ba%2Bb%2Cx%E5%B1%9E%E4%BA%8E%280%2C%CF%80%EF%BC%8F2%29%E5%80%BC%E5%9F%9F%5B-5%2C1%5D%2C%E6%B1%82a%2Cb)
x){ھ
iFřyjʆF:f*+t*ndW{46y:~aγM:I6IET6QΆ4j3552bi`U
NN5J jBhBBF 1W Y
函数fx=2asin²x-2√3asinxcosx+a+b,x属于(0,π/2)值域[-5,1],求a,b
函数fx=2asin²x-2√3asinxcosx+a+b,x属于(0,π/2)值域[-5,1],求a,b
函数fx=2asin²x-2√3asinxcosx+a+b,x属于(0,π/2)值域[-5,1],求a,b
2sin^2x=1-cos2x
2sinxcosx=sin2x
f(x)=a-acos2x-a√3sin2x+a+b
=2a+b-2a(cos2xcosπ/3+sin2xsinπ/3)
=2a+b-2acos(2x-π/3)
-5