log3 4×log4 8×log8 a=log根号3 9,则a=

log3 4×log4 8×log8 a=log根号3 9,则a= log3(4)·log4(8)·log8(m)=log4(16)则m= 设log3(4)*log4(8)*log8(m)=log4（16）那么m等于~ 若log3 4*log4 8*log8 m=log4 16求m ：若log3(4)*log4(8)*log8(m)=log4(16),则m等于( )A 1/2 B 9 C 18 D 27答案是B但为什么? log3(4)×log4(8)×log8(x)=log6(36)求X＝?A.1/2B.6C.9D.18为什么等于Log3（x）a log4 8-log8 4=? log3 4*log4 8*log8 7*log7 m=1og3 18 求M 等于多少. 化简log3(4)*log4(5)*log5(8)*log8(9)的结果是? (log3^2 + log9^4)×(log4^3 + log8^3) log3 4*log4 8*log8 m=log4 16,则m为[ ]其中3、4、8、4为底数. log3^4乘log4^8乘log8^m=log4^2麻烦过程写清楚一点.谢谢、 若log3（4）×log4（8）×log8（m）=log4（16）.则m等于?谢谢 log3^4*log4^8*log8^m=log4^2 求mlog8^3=p log3^5=q用pq表示lg5 (log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?.. (log4(3)+log8(3))*log3(2) 求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64) log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9