根号x+2+(x+y)²=0,则x²-xy等于多少?
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根号x+2+(x+y)²=0,则x²-xy等于多少?
根号x+2+(x+y)²=0,则x²-xy等于多少?
根号x+2+(x+y)²=0,则x²-xy等于多少?
因为
根号x+2≥0,(x+y)²≥0
要使得根号x+2+(x+y)²=0
根号x+2=0,(x+y)²=0
X+2=0,X+Y=0
求得,X=-2 Y=2
x²-xy=8