作业帮怎样把n^4+2n^3+3n^2+2n+1因式分解成n*(n+1)+1)^2?
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/17 00:27:25
x){lg]]yq&FyqyqF@ bg 4@gdoTO^;lC4`"@j&$th76F 10NZlhna9y: k h!B 6 DI
怎样把n^4+2n^3+3n^2+2n+1因式分解成n*(n+1)+1)^2?
怎样把n^4+2n^3+3n^2+2n+1因式分解成n*(n+1)+1)^2?
怎样把n^4+2n^3+3n^2+2n+1因式分解成n*(n+1)+1)^2?
n^4+2n^3+3n^2+2n+1
=n^4+2n^3+n^2+2n^2+2n+1
=n^2(n^2+2n+1)+2n(n+1)+1
=n^2(n+1)^2+2n(n+1)+1
=[n(n+1)+1]^2
n^4+2n^3+3n^2+2n+1
=n^4+2n^3+n^2+2n^2+2n+1
=n^2(n^2+2n+1)+2n(n+1)+1
=[n(n+1)]²+2n(n+1)+1
=[n(n+1)+1]²
n^4+2n^3+3n^2+2n+1
=n^4+2n^3+n^2+2n^2+2n+1
=n^2(n+1)^2+2n(n+1)+1
=(n(n+1)+1)^2