(0.125+0.234+0.345)×(0.234+0.345+0.456)减(0.123+0.234+0.345+0.456)×(0.234+0.345)
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(0.125+0.234+0.345)×(0.234+0.345+0.456)减(0.123+0.234+0.345+0.456)×(0.234+0.345)
(0.125+0.234+0.345)×(0.234+0.345+0.456)减(0.123+0.234+0.345+0.456)×(0.234+0.345)
(0.125+0.234+0.345)×(0.234+0.345+0.456)减(0.123+0.234+0.345+0.456)×(0.234+0.345)
设0.123+0.234+0.345=a,0.234+0.345=b
a-b=(0.123+0.234+0.345)-(0.234+0.345)=0.123
则原式=a×(b+0.456)-(a+0.456)×b
=ab+0.456a-ab-0.456b
=0.456a-0.456b
=0.456(a-b)
=0.456×0.123
=0.056088
(0.125+0.234+0.345)×(0.234+0.345+0.456)减(0.123+0.234+0.345+0.456)×(0.234+0.345)
0.123+0.234+0.345+.+0.789
0.123+0.321+0.234+0.432+0.345+0.543+……+0.789+0.987=?
化成分数 0.345 0.35 0.345 (45)循环
将数0.345、59分之17、22分之7、0.345 (45循环)从小到大排列
将数0.345、59分之17、22分之7、0.345 (45循环)从小到大排
0.345的平方-0.345乘2.69+1.345的平方(要过程)
2.34乘9.9加0.234等于?(必须简便运算)
简便运算 2.616+(10.4-0.234/0.65)*0.35
9.4×0.234的数保留两位小数是( )
三角函数的有关计算(1)求出α值 sinα=0.2514cosα=0.6538tanα=2.9516cosα=0.123cosα=0.234cosα=0.345(2)已知sinα=0.2829 ,则tanα=_______(2)已知sinα=0.2829 ,则tanα=_______ 这个请告诉我怎么求 还请问下怎么用计
3.45×3.6+0.345×64(用简便方法计算)
用方程将循环小数0.345(45循环)化为分数
把下面的小数化成分数(能化成最简的化成最简)0.08 0.25 0.7 0.34 0.125 0.6 0.04 0.12 0.455 0.8 0.36 0.65 0.15 0.04 0.1 0.7 0.17 0.56 0.25 0.24 0.48 0.125 0.33 0.75 0.675 0.37 0.25 0.07 0.345 0.15 0.04 0.25 0.225 0.09 3.2 0.34 0.06
简便计算:1.345²×0.345×2-1.345³-1.345×0.345²(过程详细+分)
8/0.125(简算)
1.345*0.345*2.69-1.345*1.345*1.345-1.345*0.345*0.345
1.345 × 0.345× 2.69 -1.345×1.345-1.345×0.345×0.345