利用“平方差公式”计算 (2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1) +1可以讲解一下吗?THANK YOU!
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 17:39:55
![利用“平方差公式”计算 (2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1) +1可以讲解一下吗?THANK YOU!](/uploads/image/z/216917-53-7.jpg?t=%E5%88%A9%E7%94%A8%E2%80%9C%E5%B9%B3%E6%96%B9%E5%B7%AE%E5%85%AC%E5%BC%8F%E2%80%9D%E8%AE%A1%E7%AE%97+%EF%BC%882%2B1%EF%BC%89%EF%BC%882%5E2%2B1%29%282%5E4%2B1%29%282%5E8%2B1%29%EF%BC%882%5E16%2B1%EF%BC%89%282%5E32%2B1%29%EF%BC%882%2B1%EF%BC%89%EF%BC%882%5E2%2B1%29%282%5E4%2B1%29%282%5E8%2B1%29%EF%BC%882%5E16%2B1%EF%BC%89%282%5E32%2B1%29+%2B1%E5%8F%AF%E4%BB%A5%E8%AE%B2%E8%A7%A3%E4%B8%80%E4%B8%8B%E5%90%97%EF%BC%9FTHANK+YOU%21)
利用“平方差公式”计算 (2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1) +1可以讲解一下吗?THANK YOU!
利用“平方差公式”计算 (2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1) +1
可以讲解一下吗?THANK YOU!
利用“平方差公式”计算 (2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1) +1可以讲解一下吗?THANK YOU!
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^8-1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^16-1)(2^16+1)(2^32+1)+1
=(2^32-1)(2^32+1)+1
=2^64-1+1
=2^64
一直用平方差公式就行了:(a-b)(a+b)=a²-b²
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您好:
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=...
=2^64-1
不明白,可以追问
如有帮助,记得采纳,谢谢
祝学习进步!
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