作业帮已知：（x+2）²+|x+y-10|=0,求3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy的值
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已知：（x+2）²+|x+y-10|=0,求3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy的值
已知：（x+2）²+|x+y-10|=0,求3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy的值
已知：（x+2）²+|x+y-10|=0,求3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy的值
（x+2）²+|x+y-10|=0
x+2=0
x+y-10=0
x=-2
y=12
3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy
=3x²y－（5x²y－2xy+x²y－2x²）－xy
=3x²y－（6x²y－2xy－2x²）－xy
=3x²y－6x²y+2xy+2x²+xy
=-x²y+3xy+2x²
=-4*12+3*(-2)*12+2*4
=-48-72+8
=-102
x=-2,y=10-x=12,3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy=-3x²y+xy+2x²=-160
请问是（x+2）²+|x+y-10|=0，求3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy在
这个算式吗？
非负数性质。必然同时为0.
可得x=-2,代入后面式子可得y=12
然后，去括号，合并得2x²-2x²y+xy=-112
因为：（x+2）²+|x+y-10|=0
所以：x+2=0 ,x+y-10=0
x=-2 , y=12
3x²y－[5x²y－﹙2xy－x²y﹚－2x²]－xy=3x²y－[5x²y－2xy+x²y－2x²]－xy=3x²y－5x²y+2xy-x²y+2x²－xy=-3x²y+xy+2x²=-3*4*12+(-3)*12+2*4=-144-36+8=-172