已知5x²-3x-5=0,则5x²-2x-(1/5x²-2x-5)=_____
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已知5x²-3x-5=0,则5x²-2x-(1/5x²-2x-5)=_____
已知5x²-3x-5=0,则5x²-2x-(1/5x²-2x-5)=_____
已知5x²-3x-5=0,则5x²-2x-(1/5x²-2x-5)=_____
已知5x²-3x-5=0,∴ 5x²-2x-5=x,5x²-2x=x+5,
则5x²-2x-(1/5x²-2x-5)
=x+5-1/x
=(x²+5x-1)/x——→已知5x²-3x-5=0,5x²-3x-5+28x=28x,5x²+25x-5=28x,【x²+5x-1=28x/5】
=(28x/5)/x
=28/5
=5.6