(2x-5)^2+(3x+1)(3x-1)>13(x^2-10) 这个方程怎么解啊?不等式
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(2x-5)^2+(3x+1)(3x-1)>13(x^2-10) 这个方程怎么解啊?不等式
(2x-5)^2+(3x+1)(3x-1)>13(x^2-10) 这个方程怎么解啊?
不等式
(2x-5)^2+(3x+1)(3x-1)>13(x^2-10) 这个方程怎么解啊?不等式
4x^2-20x+25+9x^2-1>13x^2-130
-20x+24>-130
20x
你好!
4x^2+25-20x+9x^2-1>13x^2-130
13x^2-20x+24>13x^2-130
-20x>-130-24=-154
20x<154
x<154/20=77/10
展开求解
最后求得:x<7.7
4x²-20x+25+9x²-1>13x²-130
-20x+25-1>-130
20x>154
x>77/10
4x²-20x+25+9x²-1>13x²-130
-20x+25-1>-130
20x>154
x>7.7
展开4x^2-20x+25+9x^2-1>13x^2-130
-20x=-154
x=7.7
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