化简求值 2(x²y+xy²)+2(x²y-1)-2xy²-2,其中x=-2,y=2
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/17 00:26:26
![化简求值 2(x²y+xy²)+2(x²y-1)-2xy²-2,其中x=-2,y=2](/uploads/image/z/2339111-47-1.jpg?t=%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC+2%28x%26%23178%3By%2Bxy%26%23178%3B%29%2B2%28x%26%23178%3By-1%29-2xy%26%23178%3B-2%2C%E5%85%B6%E4%B8%ADx%3D-2%2Cy%3D2)
x){3g6Q0ҨPS64Ԯ4F0 ]#۞X[adV$S8;B ",[:CRSIek $L6yvPـ9ä"Ψf ئ80c#[i҆as#LANȵ
化简求值 2(x²y+xy²)+2(x²y-1)-2xy²-2,其中x=-2,y=2
化简求值 2(x²y+xy²)+2(x²y-1)-2xy²-2,其中x=-2,y=2
化简求值 2(x²y+xy²)+2(x²y-1)-2xy²-2,其中x=-2,y=2
x+y=0
2(x²y+xy²)+2(x²y-1)-2xy²-2
=2xy(x+y)+2xy(x-y)-4
=2xy(x-y)-4
=2*2*(-2)*(-4)-4
=28
2(x²y+xy²)+2(x²y-1)-2xy²-2
=4x^2y-4
=4*(-2)^2*2-4
=32-4
=28
2(x²y+xy²)+2(x²y-1)-2xy²-2
=2x²y+2xy²+2x²y-2-2xy²-2
=4x²y-4
=4×(-2)²×2-4
=32-4
=28