已知x2+2y2-2xy+2y+1=0,求x+2y的值
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已知x2+2y2-2xy+2y+1=0,求x+2y的值
已知x2+2y2-2xy+2y+1=0,求x+2y的值
已知x2+2y2-2xy+2y+1=0,求x+2y的值
x2+2y2-2xy+2y+1=0
(x-y)^2+(y+1)^2=0
x=y,y+1=0
x=y=-1
x+2y=-3
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