如图,RT三角形ABC中,角ABC=90°,以AB为直径的圆O交AC于D,过点D的切线交BC于点E,(1)求证,DE=二分之BC;(2)若tan角C=二分之根5,DE=2,求AD的长
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![如图,RT三角形ABC中,角ABC=90°,以AB为直径的圆O交AC于D,过点D的切线交BC于点E,(1)求证,DE=二分之BC;(2)若tan角C=二分之根5,DE=2,求AD的长](/uploads/image/z/2391547-67-7.jpg?t=%E5%A6%82%E5%9B%BE%2CRT%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92ABC%3D90%C2%B0%2C%E4%BB%A5AB%E4%B8%BA%E7%9B%B4%E5%BE%84%E7%9A%84%E5%9C%86O%E4%BA%A4AC%E4%BA%8ED%2C%E8%BF%87%E7%82%B9D%E7%9A%84%E5%88%87%E7%BA%BF%E4%BA%A4BC%E4%BA%8E%E7%82%B9E%2C%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%2CDE%3D%E4%BA%8C%E5%88%86%E4%B9%8BBC%3B%282%29%E8%8B%A5tan%E8%A7%92C%3D%E4%BA%8C%E5%88%86%E4%B9%8B%E6%A0%B95%2CDE%3D2%2C%E6%B1%82AD%E7%9A%84%E9%95%BF)
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