作业帮函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2若当x∈[π/12,7π/12]时,f(x)的反函数为f//(x),求f//(1)的值.化简出来是2sin(2x+π/3)
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函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2若当x∈[π/12,7π/12]时,f(x)的反函数为f//(x),求f//(1)的值.化简出来是2sin(2x+π/3)
函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2
若当x∈[π/12,7π/12]时,f(x)的反函数为f//(x),求f//(1)的值.
化简出来是2sin(2x+π/3)
函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2若当x∈[π/12,7π/12]时,f(x)的反函数为f//(x),求f//(1)的值.化简出来是2sin(2x+π/3)
利用反函数定义
f//(1)=a
表明
f(a)=1
即
2sin(2a+π/3)=1
sin(2a+π/3)=1/2
2a+π/3=2kπ+π/6 或者 2kπ+5π/6,k是整数
即
2a=2kπ-π/6 或者 2kπ+π/2
a=kπ-π/12 或者 kπ+π/4
因为
π/12