{3x-2y+5z=02x+5y-10z=192x+3y+15z=13{x+y=3y+z=5x+z=6
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{3x-2y+5z=02x+5y-10z=192x+3y+15z=13{x+y=3y+z=5x+z=6
{3x-2y+5z=0
2x+5y-10z=19
2x+3y+15z=13
{x+y=3
y+z=5
x+z=6
{3x-2y+5z=02x+5y-10z=192x+3y+15z=13{x+y=3y+z=5x+z=6
3x-2y+5z=0 (1)
2x+5y-10z=19 (2)
2x+3y+15z=13 (3)
(2)-(3) 得2y-25z=6 (4)
(2)*3-(1)*2得19y-40z=57 (5)
(4)*19-(5)*2得z=0
将z=0带入(4)得y=3
将y=3、z=0带入(3)得x=2
所以 x=2
y=3
z=0
补充:x+y=3 (1)
y+z=5 (2)
x+z=6 (3)
〔(1)+(2)+(3)〕÷2 得 x+y+z=7 (4)
(4)-(1)得 z=4
(4)-(2)得 x=2
(4)-(3)得 y=1
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x+2y+3z=23 y-z=5 x+2z=10
x/2=y/3=z/5 x+3y-z/x-3y+z
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
{3x-2y+5z=02x+5y-10z=192x+3y+15z=13{x+y=3y+z=5x+z=6
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
x+y+2z=5 2x-y-z=4 3x+y-3z=10
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
2x+y-z=3 5x+3y-z=10 求x+y+z=
-2X+3Y+Z=-4-X-5Y-2Z=-13X+Y-Z=10
x+y-z=5,2x+3y+z=10,x-2y-z=20求方程组
x+y-z=5 2x+3y+z=10 x-2y-z=20 速解,
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31
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已知4x-3y-6z=0,x+2y-7z=0,求5x+2y-z/2x-3y-10z