二次函数f(x)=x²+qx+r满足1/(m+2)+q/(m+1)+r/m=0其中m>0(1)判断f[m/(m+1)]的正负(2)求证:方程f(X)=0在区间(0,1)内恒有解.
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![二次函数f(x)=x²+qx+r满足1/(m+2)+q/(m+1)+r/m=0其中m>0(1)判断f[m/(m+1)]的正负(2)求证:方程f(X)=0在区间(0,1)内恒有解.](/uploads/image/z/2446011-27-1.jpg?t=%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%28x%29%3Dx%26%23178%3B%2Bqx%2Br%E6%BB%A1%E8%B6%B31%2F%28m%2B2%29%2Bq%2F%EF%BC%88m%2B1%EF%BC%89%2Br%2Fm%3D0%E5%85%B6%E4%B8%ADm%EF%BC%9E0%281%29%E5%88%A4%E6%96%ADf%5Bm%2F%28m%2B1%29%5D%E7%9A%84%E6%AD%A3%E8%B4%9F%EF%BC%882%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A%E6%96%B9%E7%A8%8Bf%28X%29%3D0%E5%9C%A8%E5%8C%BA%E9%97%B4%EF%BC%880%2C1%EF%BC%89%E5%86%85%E6%81%92%E6%9C%89%E8%A7%A3.)
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二次函数f(x)=x²+qx+r满足1/(m+2)+q/(m+1)+r/m=0其中m>0(1)判断f[m/(m+1)]的正负(2)求证:方程f(X)=0在区间(0,1)内恒有解.
二次函数f(x)=x²+qx+r满足1/(m+2)+q/(m+1)+r/m=0其中m>0
(1)判断f[m/(m+1)]的正负
(2)求证:方程f(X)=0在区间(0,1)内恒有解.
二次函数f(x)=x²+qx+r满足1/(m+2)+q/(m+1)+r/m=0其中m>0(1)判断f[m/(m+1)]的正负(2)求证:方程f(X)=0在区间(0,1)内恒有解.