1/3+1/5+1/7+1/9+1/11+...+1/99

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1/3+1/5+1/7+1/9+1/11+...+1/99
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1/3+1/5+1/7+1/9+1/11+...+1/99
1/3+1/5+1/7+1/9+1/11+...+1/99

1/3+1/5+1/7+1/9+1/11+...+1/99
由题目可以看出,期通项公式为:1/(2n+1)
因为:
1+1/2+1/3+……+1/(2n+1)=ln(2n+1)+0.5772157.(1)
1+1/2+1/3+……+1/n=lnn+0.5772157 变形,两边同时除2
1/2+1/4+……+1/2n=1/2*lnn+0.5772157/2...(2)
(1)-(2)得
1+1/3+……+1/(2n+1)=ln(2n+1)-1/2*lnn+0.5772157/2
所以:1/3+……+1/(2n+1)=ln(2n+1)-1/2*lnn-0.71138215
1/(2n+1)=1/99时,x=49
把x=49代入上式即可

简算:1/1*3+1/3*5+1/5*7+1/7*9+1/9*11 (1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1 1/1*3+1/3*5+1/5*7+1/7*9+1/9*11 (1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1 计算:1/3*5+1/5*7+1/7*9+1/9*11+1/11*13 1×3/1+3×5/1+5×7/1+7×9/1+9×11/1+11×13/1简便运算 计算：2/3*5+1/5*7+1/7*9+1/9*11+1/11*13 1/3+1/5+1/7+1/9+1/11+1/13+1/15= 1/3+1/5+1/7+1/9+1/11+1/13+...+1/99=? 1/1*3*5+1/3*5*7+1/5*7*9+1/7*9*11+1/9*11*13+1/11*13*15怎么计算 1/(1*3*5)+1/(3*5*7)+1/(5*7*9)+1/(7*9*11)+1/(9*11*13)+1/(11*13*15)等于多少 5 7 -5 3 9 -1 11 -3 1 1+3+5+7+9+11+.+99 1-3+5-7+9-11+13 1-3+5-7+9-11+.求救 1+3+5+7+9+11=? 1,3,5,7,9,11,15 计算:1-3 5-7 9-11