matlab 超越方程e1=(1.09+13.43*i)^2e2=2.25k0 =3.2429a= 1.0e-09 *[10 50 100 500 1000 5000 10000 50000 100000]k1=solve('tan(k1*a)+tanh(-e1*(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')
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![matlab 超越方程e1=(1.09+13.43*i)^2e2=2.25k0 =3.2429a= 1.0e-09 *[10 50 100 500 1000 5000 10000 50000 100000]k1=solve('tan(k1*a)+tanh(-e1*(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')](/uploads/image/z/2476964-20-4.jpg?t=matlab+%E8%B6%85%E8%B6%8A%E6%96%B9%E7%A8%8Be1%3D%281.09%2B13.43%2Ai%29%5E2e2%3D2.25k0+%3D3.2429a%3D+1.0e-09+%2A%5B10+50+100+500+1000+5000+10000+50000+100000%5Dk1%3Dsolve%28%27tan%28k1%2Aa%29%2Btanh%28-e1%2A%28%28%28e1-e2%29%2Ak0%5E2+%2Bk1%5E2%29%29%5E0.5%2Fk1%2Fe2%29%3D0%27%2C%27k1%27%29)
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matlab 超越方程e1=(1.09+13.43*i)^2e2=2.25k0 =3.2429a= 1.0e-09 *[10 50 100 500 1000 5000 10000 50000 100000]k1=solve('tan(k1*a)+tanh(-e1*(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')
matlab 超越方程
e1=(1.09+13.43*i)^2
e2=2.25
k0 =3.2429
a= 1.0e-09 *[10 50 100 500 1000 5000 10000 50000 100000]
k1=solve('tan(k1*a)+tanh(-e1*(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')
matlab 超越方程e1=(1.09+13.43*i)^2e2=2.25k0 =3.2429a= 1.0e-09 *[10 50 100 500 1000 5000 10000 50000 100000]k1=solve('tan(k1*a)+tanh(-e1*(((e1-e2)*k0^2 +k1^2))^0.5/k1/e2)=0','k1')
这类题可以用solve()函数,只能一个一个地求.求解方法如下: