C语言课本题目求详解,设有int x=2,y=3,z=5,s=1,t=2,则表达式!(a+b)+c-1&&b+c/2的值为多少课本的答案是3,为啥,求详解
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/16 13:48:28
![C语言课本题目求详解,设有int x=2,y=3,z=5,s=1,t=2,则表达式!(a+b)+c-1&&b+c/2的值为多少课本的答案是3,为啥,求详解](/uploads/image/z/2478655-55-5.jpg?t=C%E8%AF%AD%E8%A8%80%E8%AF%BE%E6%9C%AC%E9%A2%98%E7%9B%AE%E6%B1%82%E8%AF%A6%E8%A7%A3%2C%E8%AE%BE%E6%9C%89int+x%3D2%2Cy%3D3%2Cz%3D5%2Cs%3D1%2Ct%3D2%2C%E5%88%99%E8%A1%A8%E8%BE%BE%E5%BC%8F%21%EF%BC%88a%2Bb%EF%BC%89%2Bc-1%26%26b%2Bc%2F2%E7%9A%84%E5%80%BC%E4%B8%BA%E5%A4%9A%E5%B0%91%E8%AF%BE%E6%9C%AC%E7%9A%84%E7%AD%94%E6%A1%88%E6%98%AF3%2C%E4%B8%BA%E5%95%A5%2C%E6%B1%82%E8%AF%A6%E8%A7%A3)
x͐N@_.
ēm/> A҈TAMj"AABQHl֗'^Ǔ'e2;|ISCOgi
nvxG4:3HD9VnߧylRyF2d =Lc/kUaAV)ccviy""[_ /|6S
>&Y*~j[a|5-֤FuzA{m͙.=wvgeÛ^0MzZ,s Ija`:8gNkW,V醄Z6_f,
C语言课本题目求详解,设有int x=2,y=3,z=5,s=1,t=2,则表达式!(a+b)+c-1&&b+c/2的值为多少课本的答案是3,为啥,求详解
C语言课本题目求详解,设有int x=2,y=3,z=5,s=1,t=2,则表达式!(a+b)+c-1&&b+c/2的值为多少
课本的答案是3,为啥,求详解
C语言课本题目求详解,设有int x=2,y=3,z=5,s=1,t=2,则表达式!(a+b)+c-1&&b+c/2的值为多少课本的答案是3,为啥,求详解
破书出的烂题.
答案永远不可能为3 .
表达式!(a+b)+c-1&&b+c/2中的变量跟前面的定义没有星点关系,
而且该表达式的本质是&&,
即
(!(a+b)+c-1) && (b+c/2)//最后所得要么是1,要么是0