已知cosθ=-3/5,θ∈(派/2,派),求sin(θ+ 派/3)马上!已知tanα=2求tan(α-π/4)的值已知cosθ=-5/13,θ∈(派,3派/2),求cos(θ+π/6)
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![已知cosθ=-3/5,θ∈(派/2,派),求sin(θ+ 派/3)马上!已知tanα=2求tan(α-π/4)的值已知cosθ=-5/13,θ∈(派,3派/2),求cos(θ+π/6)](/uploads/image/z/2478676-4-6.jpg?t=%E5%B7%B2%E7%9F%A5cos%CE%B8%3D-3%2F5%2C%CE%B8%E2%88%88%EF%BC%88%E6%B4%BE%2F2%2C%E6%B4%BE%EF%BC%89%2C%E6%B1%82sin%28%CE%B8%2B+%E6%B4%BE%2F3%EF%BC%89%E9%A9%AC%E4%B8%8A%21%E5%B7%B2%E7%9F%A5tan%CE%B1%3D2%E6%B1%82tan%28%CE%B1-%CF%80%2F4%29%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A5cos%CE%B8%3D-5%2F13%2C%CE%B8%E2%88%88%EF%BC%88%E6%B4%BE%EF%BC%8C3%E6%B4%BE%2F2%EF%BC%89%EF%BC%8C%E6%B1%82cos%28%CE%B8%2B%CF%80%2F6%29)
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已知cosθ=-3/5,θ∈(派/2,派),求sin(θ+ 派/3)马上!已知tanα=2求tan(α-π/4)的值已知cosθ=-5/13,θ∈(派,3派/2),求cos(θ+π/6)
已知cosθ=-3/5,θ∈(派/2,派),求sin(θ+ 派/3)
马上!
已知tanα=2求tan(α-π/4)的值
已知cosθ=-5/13,θ∈(派,3派/2),求cos(θ+π/6)
已知cosθ=-3/5,θ∈(派/2,派),求sin(θ+ 派/3)马上!已知tanα=2求tan(α-π/4)的值已知cosθ=-5/13,θ∈(派,3派/2),求cos(θ+π/6)
cosθ=-3/5,θ∈(π/2,π),
所以sinθ>0
因为(sinθ)^2+(cosθ)^2=1
所以sinθ=4/5
sin(θ+π/3)=sinθcosπ/3+cosθsinπ/3=(4/5)*(1/2)+(-3/5)*(√3/2)
=(4-3√3)/10
十分之四减三倍根号三
呵呵,简单
先教你和化积差吧
sin(θ+⊙)=sinθcos⊙+cosθsin⊙
所以
又因为sinθ=4/5
所以:sin(θ+ ∏/3)=2/5+0.3倍根号3
tanα=2求tan(α-π/4)的值
tan(α-π/4)=【tanα+tanπ/4】/【1+tanαtanπ/4】
所以,答案为1
十分之四减三倍根号三