已知sin(π-a)=4/5,a属于(0,π/2) 求sin2a-cos^2 a/2的值 求函数f(x)=5/6 cosa sin2x-1/2cos2x的值第二问是 求函数f(x)=5/6* cosa *sin2x-1/2*cos2x的值
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![已知sin(π-a)=4/5,a属于(0,π/2) 求sin2a-cos^2 a/2的值 求函数f(x)=5/6 cosa sin2x-1/2cos2x的值第二问是 求函数f(x)=5/6* cosa *sin2x-1/2*cos2x的值](/uploads/image/z/2483140-4-0.jpg?t=%E5%B7%B2%E7%9F%A5sin%28%CF%80-a%29%3D4%2F5%2Ca%E5%B1%9E%E4%BA%8E%EF%BC%880%2C%CF%80%2F2%EF%BC%89+%E6%B1%82sin2a-cos%5E2+a%2F2%E7%9A%84%E5%80%BC+%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3D5%2F6+cosa+sin2x-1%2F2cos2x%E7%9A%84%E5%80%BC%E7%AC%AC%E4%BA%8C%E9%97%AE%E6%98%AF+%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%3D5%2F6%2A+cosa+%2Asin2x-1%2F2%2Acos2x%E7%9A%84%E5%80%BC)
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