作业帮(log4^3+log8^3)(log3^2+log9^2)详细计算过程.~
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/14 02:09:12
x)O73Rqƚ qkgb^[|۟֫I*'
^;m~7~[
C}#-Z# P&11f0E
Z
A
4rҍ5f-PU5H(473la;Nnc} Ov>۴ig>_rь'l
(log4^3+log8^3)(log3^2+log9^2)详细计算过程.~
(log4^3+log8^3)(log3^2+log9^2)
详细计算过程.~
(log4^3+log8^3)(log3^2+log9^2)详细计算过程.~
原式=(1/2*log2^3+1/3*log2^3)(log3^2+1/2*log3^2)
=(5/6*log2^3) * (3/2*log3^2)
={5/6*(lg3)/(lg2)} * {3/2*(lg2/lg3)}
=5/4
答案对吗?我很久没做这种题了
(log4(3)+log8(3))*log3(2)
(log3^2 + log9^4)×(log4^3 + log8^3)
(log3 2+log9 2)*(log4 3+log8 3)求值
化简(log4(3)+log8(3))(log3(2)+log9(2))
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?..
(log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32)
求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64)
急 求 （log3 2+log9 2）-（log4 3+log8 3）求 （log3 2+log9 2）-（log4 3+log8 3）
[log4(3)+log8(3)]*log3(2)答案是1/3么
求(log3^2 + log9^2)×（log4^3 + log8^3)的值.请给出过程,谢谢!
求值(log3(2)+log9(2))*(log4(3)+log8(3))打括号是真数.
【（log4）^3+.（log8）^3】【.（log3）^2+.（log9）^2】=几啊
(log4^3+log8^3)(log3^2+log9^2)详细计算过程.~
化简此式（log4 3+log8 3)×（log3 2+log9 2）
(log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)=
计算：1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a
log3 4×log4 8×log8 a=log根号3 9,则a=