tanα=2,(1+cos²α)/(2sin²α-3sinαcosα)求解(1+cos²α)/(2sin²α-3sinαcosα)=多少
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tanα=2,(1+cos²α)/(2sin²α-3sinαcosα)求解(1+cos²α)/(2sin²α-3sinαcosα)=多少
tanα=2,(1+cos²α)/(2sin²α-3sinαcosα)
求解(1+cos²α)/(2sin²α-3sinαcosα)=多少
tanα=2,(1+cos²α)/(2sin²α-3sinαcosα)求解(1+cos²α)/(2sin²α-3sinαcosα)=多少
tanα=2 sinα/cosα=2 sinα=2cosα 分母2sin²α-3sinαcosα=8cos²α-6cos²α=2cos²α
(1+cos²α)/(2sin²α-3sinαcosα)=(sin²α+cos²α+cos²α)/2cos²α=(tanα)²+2=4+2=6