化简2sin[(π/2)+α]-cos(-π+α)/cos(3π+aα)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 23:09:01
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化简2sin[(π/2)+α]-cos(-π+α)/cos(3π+aα)
化简2sin[(π/2)+α]-cos(-π+α)/cos(3π+aα)
化简2sin[(π/2)+α]-cos(-π+α)/cos(3π+aα)
化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α)
[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
2sinα*cosα*cos(2π-α)+cos(π+2α)*cosα*tanα化简!
化简[sin(π/2-α)cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α)
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
化简:(sin²αtanα+cos²α/tanα+2sinαcosα)sinαcosα
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(sinα+cosα)^2化简
化简sin²α-2sinαcosα+1
若cosα>sinα,(-π/2
化简(sinα+cosβ)^2
化简:sin(-a)cos(2π+a)sin(-a-π)
化简:sin^2αcos^2β-cos^2αsin^2β+cos^2α-cos^2β具体步骤,
化简sin(α+β)-2cosαsinβ/2cosαcosβ-cos(α+β)
化简sin^2α+sin^2β+2sinαsinβcos(α+β)
sin(α+β)-2sinαcosβ/2sinαsinβ+cos(α+β)化简