tan(π/4+a)=2,求1/(2sinacosa+cosa^2)值我做出tana=1/3,tan2a=3/4,原式=1/(sin2a+cos2a+sina^2)接下来就不会了...
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![tan(π/4+a)=2,求1/(2sinacosa+cosa^2)值我做出tana=1/3,tan2a=3/4,原式=1/(sin2a+cos2a+sina^2)接下来就不会了...](/uploads/image/z/2495302-70-2.jpg?t=tan%28%CF%80%2F4%2Ba%29%3D2%2C%E6%B1%821%2F%282sinacosa%2Bcosa%5E2%29%E5%80%BC%E6%88%91%E5%81%9A%E5%87%BAtana%3D1%2F3%2Ctan2a%3D3%2F4%2C%E5%8E%9F%E5%BC%8F%3D1%2F%28sin2a%2Bcos2a%2Bsina%5E2%29%E6%8E%A5%E4%B8%8B%E6%9D%A5%E5%B0%B1%E4%B8%8D%E4%BC%9A%E4%BA%86...)
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tan(π/4+a)=2,求1/(2sinacosa+cosa^2)值我做出tana=1/3,tan2a=3/4,原式=1/(sin2a+cos2a+sina^2)接下来就不会了...
tan(π/4+a)=2,求1/(2sinacosa+cosa^2)值
我做出tana=1/3,tan2a=3/4,原式=1/(sin2a+cos2a+sina^2)
接下来就不会了...
tan(π/4+a)=2,求1/(2sinacosa+cosa^2)值我做出tana=1/3,tan2a=3/4,原式=1/(sin2a+cos2a+sina^2)接下来就不会了...
1/(2sin(a)cos(a)+cos(a)^2)
=(sin(a)^2+cos(a)^2)/(2sin(a)cos(a)+cos(a)^2),
分子分母同除以cos(a)^2得
(tan(a)^2+1)/(2tan(a)+1)
=(1/9+1)/(2/3+1)
=2/3