如图,在三角形ABC中,角ACB=90°,AC=BC,CE垂直BE,CE与AB相交与点F,AD垂直CF与点D,且AD平分角FAC,求证:AD=2BE+EF
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/08 04:32:39
![如图,在三角形ABC中,角ACB=90°,AC=BC,CE垂直BE,CE与AB相交与点F,AD垂直CF与点D,且AD平分角FAC,求证:AD=2BE+EF](/uploads/image/z/2500349-5-9.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92ACB%3D90%C2%B0%2CAC%3DBC%2CCE%E5%9E%82%E7%9B%B4BE%2CCE%E4%B8%8EAB%E7%9B%B8%E4%BA%A4%E4%B8%8E%E7%82%B9F%2CAD%E5%9E%82%E7%9B%B4CF%E4%B8%8E%E7%82%B9D%2C%E4%B8%94AD%E5%B9%B3%E5%88%86%E8%A7%92FAC%2C%E6%B1%82%E8%AF%81%EF%BC%9AAD%3D2BE%2BEF)
xSnPRWqb[ #n M+TRD*
Qj@iS";.\I\Mw]ygf=3.6Oͨ;R߾@('
8Ql?0e
ѻۣ̰!t퇃`NgBxgvJ
Өل)͋Og÷cuaux#5IX\;:^{urQLR+Wzu*ÌWR+SUtn"Bjn^xܼk,=kNA͗Gg~yA![{~!q3wk@t-.FNr1\R."(0R2yfM.:Z
X