已知abc为三角形三边长,且方程b(x^2-1)-2ax+c(x^2+1)=0有两个相等吨实数根.判断形状由原式得(b+c)x^2 - 2ax + (c-b) = 0这步怎么来的
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![已知abc为三角形三边长,且方程b(x^2-1)-2ax+c(x^2+1)=0有两个相等吨实数根.判断形状由原式得(b+c)x^2 - 2ax + (c-b) = 0这步怎么来的](/uploads/image/z/2504549-29-9.jpg?t=%E5%B7%B2%E7%9F%A5abc%E4%B8%BA%E4%B8%89%E8%A7%92%E5%BD%A2%E4%B8%89%E8%BE%B9%E9%95%BF%2C%E4%B8%94%E6%96%B9%E7%A8%8Bb%28x%5E2-1%29-2ax%2Bc%28x%5E2%2B1%29%3D0%E6%9C%89%E4%B8%A4%E4%B8%AA%E7%9B%B8%E7%AD%89%E5%90%A8%E5%AE%9E%E6%95%B0%E6%A0%B9.%E5%88%A4%E6%96%AD%E5%BD%A2%E7%8A%B6%E7%94%B1%E5%8E%9F%E5%BC%8F%E5%BE%97%EF%BC%88b%2Bc%29x%5E2+-+2ax+%2B+%28c-b%29+%3D+0%E8%BF%99%E6%AD%A5%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84)
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