如图,已知△ABC为等边三角形,D为BC上一点,以AD为边作∠ADE=60°,DE与△ABC的外.如图,已知△ABC为等边三角形,D为BC上一点,以AD为边作∠ADE=60°,DE与△ABC的外角平分线CE交与点E,连接AE,请你判断△ADE的
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![如图,已知△ABC为等边三角形,D为BC上一点,以AD为边作∠ADE=60°,DE与△ABC的外.如图,已知△ABC为等边三角形,D为BC上一点,以AD为边作∠ADE=60°,DE与△ABC的外角平分线CE交与点E,连接AE,请你判断△ADE的](/uploads/image/z/2505633-33-3.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E4%B8%BA%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2CD%E4%B8%BABC%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%BB%A5AD%E4%B8%BA%E8%BE%B9%E4%BD%9C%E2%88%A0ADE%3D60%C2%B0%2CDE%E4%B8%8E%E2%96%B3ABC%E7%9A%84%E5%A4%96.%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E4%B8%BA%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2CD%E4%B8%BABC%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%BB%A5AD%E4%B8%BA%E8%BE%B9%E4%BD%9C%E2%88%A0ADE%3D60%C2%B0%2CDE%E4%B8%8E%E2%96%B3ABC%E7%9A%84%E5%A4%96%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BFCE%E4%BA%A4%E4%B8%8E%E7%82%B9E%2C%E8%BF%9E%E6%8E%A5AE%2C%E8%AF%B7%E4%BD%A0%E5%88%A4%E6%96%AD%E2%96%B3ADE%E7%9A%84)
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