1、sin(2x+B)/sinx - 2cos(x+B)=sinB/sinx2、sinx+sinB)^2 + (cosx+cosB)^2=4cos^2*x-B/2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/27 21:08:13
xQ;j@ʖV!$ȦJ㈨0Kp& tB̠| WYfgWt:o}{Fd삣 ` `rA5{<%*m:__Q_űq~:qWW4DUgzv?JCCRag"eMnvyBl
Oˁ5!{`8Ԇdń4Qy9Zm\bn1N骑
1、sin(2x+B)/sinx - 2cos(x+B)=sinB/sinx2、sinx+sinB)^2 + (cosx+cosB)^2=4cos^2*x-B/2
1、sin(2x+B)/sinx - 2cos(x+B)=sinB/sinx
2、sinx+sinB)^2 + (cosx+cosB)^2=4cos^2*x-B/2
1、sin(2x+B)/sinx - 2cos(x+B)=sinB/sinx2、sinx+sinB)^2 + (cosx+cosB)^2=4cos^2*x-B/2
1.左边=[sinx*cos(x+b)+cosx*sin(x+b)]/sinx-2cos(x+b)
=cos(x+b)+[cosx*sin(x+b)]/sinx-2cos(x+b)
=[cosx*sin(x+b)]/sinx-cos(x+b)
=[cosx*sin(x+b)-2sinx*cos(x+b)]/sinx
={sin[(x+b)-x}/sinx
=sinb/sinx=右边.
2.左边=(sinx+sinB)^2 + (cosx+cosB)^2
=(sinx)^2+2sinx*sinb+(sinb)^2+(cosx)^2+2cosx*cosb+(cosb)^2
=2+2cos(x-b)
=4{cos[(x-B)/2 ]}^2=右边.
(sinx-1)tanx怎么化简成[(sinx-sinπ/2)/sin(x+π/2)]sinx,x趋于π/2
(sin^x/sinx-cosx)-sinx+cosx/tan^2x-1
1-2sinx*sin(60+x)sin(60-x)
cosx-sinx/1+sin^2x不定积分
sinx/(1+sin^2x)的积分
判断f(x)=(1+sinx+sin^2x)/(1+sinx)奇偶性
sinx=1/3,sin(x+y)=1,求sin(2y+x)=?
S(1-sin^2x)d(sinx)为什么=sinx-1/3sin^3x?
求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx
化简[sin^2(x)]/(sinx-cosx)-(sinx+cosx)/[tan^2(x)-1]-sinx
求最值:(1)y=-2(sin^2)x+2sinx+1 (2)y=[2sinx-1]/[sinx+3]
写出下列等式x的集合 (1)√(1-sin^x)=-cosx (2)√(1+sinx/1-sinx)-√(1-sinx/1+sin)
x-0 x^2sin(1/x)/sinx
sinx/x,(sinx/x)^2,sin(x^2)/(x^2)的大小 x∈(0,1]
求证sin^2x/sinx-cosx-(sinx+cosx)/(tan^2-1)=sinx+cosx谢谢GGJJ
求函数的值域:(1)y=|sinx|-2sinx (2)y=sin|x| |sinx|
求函数的值域:(1)y=|sinx|-2sinx (2)y=sin|x|+|sinx|
(1+Sinx+Cosx+SinxCosx)/(Sinx+Sin^2 x)怎么化简成(Cscx+1+Cotx+Cosx)/(1+Sinx)?