已知(x+1)^2+|y-1|=0,求2(xy-5xy^2)-(3xy^2-xy)的值.

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已知(x+1)^2+|y-1|=0,求2(xy-5xy^2)-(3xy^2-xy)的值.
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已知(x+1)^2+|y-1|=0,求2(xy-5xy^2)-(3xy^2-xy)的值.
已知(x+1)^2+|y-1|=0,求2(xy-5xy^2)-(3xy^2-xy)的值.

已知(x+1)^2+|y-1|=0,求2(xy-5xy^2)-(3xy^2-xy)的值.
(x+1)^2+|y-1|=0
x+1=0 x=-1
y-1=0 y=1
2(xy-5xy^2)-(3xy^2-xy)
=2xy-10xy²-3xy²+xy
=3xy-13xy²
=3x(-1)x1-13x(-1)x1²
=-3+13
=10
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