若x^3m=4,y^3n=5,求(x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 14:26:20
若x^3m=4,y^3n=5,求(x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n的值
x){ѽ"8D28TƦ{:*r5㌵5*) CہC+LLZ6I*ҧAv6Tt]_ )V+3٦ bP K4 0 .2Z$A=dlVV{L!yP'SIfFf"| b(/{:gœ]}mLKod`=5Y"$Glg

若x^3m=4,y^3n=5,求(x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n的值
若x^3m=4,y^3n=5,求(x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n的值

若x^3m=4,y^3n=5,求(x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n的值
(x^2m)^3+(y^n)^3-x^2m*y^n*x^4m*y^2n
=x^6m+y^3n-x^6my^3n
=(x^3m)^2+y^3n-(x^3m)^2*y^3n
=4^2+5-4^2*5
=-59

(x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n
=(x^3m)^2+y^3n-x^6m*y^3n
=4^2+5-(x^3m)^2*5
=13-4^2*5
=13-80
=-67

(x^2m)^3+(y^n)^3—x^2m·y^n·x^4m·y^2n
=16+2-16×5
=-59
关键在于(x^2m)^3=(x^3m)^2类似的互换