已知代数式2a^3b^n+1与-3a^m-2b^2是同类项,则2m+3n=
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 14:08:34
![已知代数式2a^3b^n+1与-3a^m-2b^2是同类项,则2m+3n=](/uploads/image/z/2517515-35-5.jpg?t=%E5%B7%B2%E7%9F%A5%E4%BB%A3%E6%95%B0%E5%BC%8F2a%5E3b%5En%2B1%E4%B8%8E-3a%5Em-2b%5E2%E6%98%AF%E5%90%8C%E7%B1%BB%E9%A1%B9%2C%E5%88%992m%2B3n%3D)
x){}K^lꆧ{㌓
5N5J3z6c =7~pӎFy6IE/$dR0겅nӹ:yZ h$A=b`w=!bR444*5J5jBFO',_lZ^~,Ɏ]@ |&"==Hj5~Ј?7$ek
ЪgkƇ
,7
已知代数式2a^3b^n+1与-3a^m-2b^2是同类项,则2m+3n=
已知代数式2a^3b^n+1与-3a^m-2b^2是同类项,则2m+3n=
已知代数式2a^3b^n+1与-3a^m-2b^2是同类项,则2m+3n=
代数式2a^3b^n+1与-3a^m-2b^2是同类项
所以
3=m-2
n+1=2
即
m=5,n=1
所以
2m+3n=10+3=13
2a^3b^n+1与-3a^m-2b^2?
应该是2(a^3)b^(n+1)与-3a^(m-2)b^2吧?
如果是的话:
因为:2(a^3)b^(n+1)与-3a^(m-2)b^2是同类项,
所以:m-2=3、n+1=2
解得:m=5、n=1
因此:2m+3n=2×5+3×1=13