当x、y为实数,满足x²+3y²-12y+12=0,求y的x次方
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当x、y为实数,满足x²+3y²-12y+12=0,求y的x次方
当x、y为实数,满足x²+3y²-12y+12=0,求y的x次方
当x、y为实数,满足x²+3y²-12y+12=0,求y的x次方
x²+3y²-12y+12=x^2+3(y^2-4y+4)=x^2+3(y-2)^2=0,x=0,y=2,y^x=2^0=1