已知x-y=6,则½x²-xy+½y²=_____
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已知x-y=6,则½x²-xy+½y²=_____
已知x-y=6,则½x²-xy+½y²=_____
已知x-y=6,则½x²-xy+½y²=_____
½x²-xy+½y²
=½(x²-2xy+y²)
=½(x-y)²
=½*(6)²
=18
原式=½(x²-2xy+y²)
=½(x-y)²
=½×6²
=18