已知a+b=2(b>0),则当a=什么时,1/2绝对值(a)+绝对值(a)/b取得最小值这道题目我是这样想的,把1/2绝对值(a),上的分子1换成1/2(a+b),所以1/2*(a+b)/2绝对值(a)=1/4*a/绝对值a+1/4*b/绝对值a,所以原式y=1/4*
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![已知a+b=2(b>0),则当a=什么时,1/2绝对值(a)+绝对值(a)/b取得最小值这道题目我是这样想的,把1/2绝对值(a),上的分子1换成1/2(a+b),所以1/2*(a+b)/2绝对值(a)=1/4*a/绝对值a+1/4*b/绝对值a,所以原式y=1/4*](/uploads/image/z/2518560-0-0.jpg?t=%E5%B7%B2%E7%9F%A5a%2Bb%3D2%28b%3E0%29%2C%E5%88%99%E5%BD%93a%3D%E4%BB%80%E4%B9%88%E6%97%B6%2C1%2F2%E7%BB%9D%E5%AF%B9%E5%80%BC%EF%BC%88a%29%2B%E7%BB%9D%E5%AF%B9%E5%80%BC%EF%BC%88a%29%2Fb%E5%8F%96%E5%BE%97%E6%9C%80%E5%B0%8F%E5%80%BC%E8%BF%99%E9%81%93%E9%A2%98%E7%9B%AE%E6%88%91%E6%98%AF%E8%BF%99%E6%A0%B7%E6%83%B3%E7%9A%84%2C%E6%8A%8A1%2F2%E7%BB%9D%E5%AF%B9%E5%80%BC%EF%BC%88a%29%2C%E4%B8%8A%E7%9A%84%E5%88%86%E5%AD%901%E6%8D%A2%E6%88%901%2F2%28a%2Bb%29%2C%E6%89%80%E4%BB%A51%2F2%2A%EF%BC%88a%2Bb%29%2F2%E7%BB%9D%E5%AF%B9%E5%80%BC%EF%BC%88a%29%3D1%2F4%2Aa%2F%E7%BB%9D%E5%AF%B9%E5%80%BCa%2B1%2F4%2Ab%2F%E7%BB%9D%E5%AF%B9%E5%80%BCa%2C%E6%89%80%E4%BB%A5%E5%8E%9F%E5%BC%8Fy%3D1%2F4%2A)
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