若x+y=3,xy=6.求x³y+2x²y²+xy³的值
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若x+y=3,xy=6.求x³y+2x²y²+xy³的值
若x+y=3,xy=6.求x³y+2x²y²+xy³的值
若x+y=3,xy=6.求x³y+2x²y²+xy³的值
原式=xy(x²+2xy+y²)
=xy(x+y)²
=6×3²
=54
x³y+2x²y²+xy³
提取xy得:xy(x²+2xy+y²)=xy(x+y)²=54