作业帮化简求值2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1,y=2011/2012
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/02 02:48:05
![化简求值2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1,y=2011/2012](/uploads/image/z/2519226-18-6.jpg?t=%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC2x%26%23178%3By-%5Bx%26%23178%3By%2B2%28x%26%23178%3By-xy%29%5D%2By%2C%E5%85%B6%E4%B8%ADx%26%23178%3B%3D2x%2B1%2Cy%3D2011%2F2012)
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化简求值2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1,y=2011/2012
化简求值2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1,y=2011/2012
化简求值2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1,y=2011/2012
2x²y-[x²y+2(x²y-xy)]+y
=2x²y-(x²y+2x²y-2xy)+y
=2x²y-(3x²y-2xy)+y
=2x²y-3x²y+2xy+y
=-x²y+2xy+y
=-y(x²-2x-1)
=-y[x²-(2x+1)]
=-(2011/2012)(x²-x²)
=0
原式=2x²y-[x²y+2xy（x-1）]+y=2x²y-[xy（x+2x-2）]+y=-x²y+2xy+y=y（1+2x-x²）=0
2x²y-[x²y+2(x²y-xy)]+y
=2x²y-[x²y+2xy(x-1)]+y
=2x²y-[x²y+2xy*2x]+y
=-3x²y+y
后面不会了